A wire of density 8 x 10 3 kg m -3 is stretched between two clamps 0. 5 m apart. The extension developed in the wire is 3. 2 x 10 -4 m. If Y = 8 x 10 10 N m -2 , the fundamental frequency of vibration in the wire will be_____Hz
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(80)
Using the relation of Young's modulus,
The linear mass density is 
So,
Substituting the values,
The fundamental frequency is given by 
= 8 x 10 = 80 m s -1 Therefore,
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